Monday, March 20, 2006
All credit to those of you willing to have a go at last week's maths problem. Some plausible answers but I'm going to go with my father-in-law on this one. His answer below.
Total weight of coal 7 x 56 lb = 392 lbs
No of cwt 392 divided by 112 = 3.5 cwt
Cost of coal 13/10 1/2 x 3.5 = £2.08s 06 3/4d (pounds shillings and
pence)
Balance of money £5.00 - £2.08.6 3/4d = £2.11.05 1/4d
Cost of shoes (guinea) = £1.01.00d
Pocket money (half crown) = 2s.06p (shillings and pence)
How much did she have left? = £1.07.11 1/4d ("one pound seven shillings and elevenpence farthing")
(£2.11.05 1/4d - £1.01.00d - 0.02.06d (all pounds shillings and pence)
Current weight 77.4 kg
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Total weight of coal 7 x 56 lb = 392 lbs
No of cwt 392 divided by 112 = 3.5 cwt
Cost of coal 13/10 1/2 x 3.5 = £2.08s 06 3/4d (pounds shillings and
pence)
Balance of money £5.00 - £2.08.6 3/4d = £2.11.05 1/4d
Cost of shoes (guinea) = £1.01.00d
Pocket money (half crown) = 2s.06p (shillings and pence)
How much did she have left? = £1.07.11 1/4d ("one pound seven shillings and elevenpence farthing")
(£2.11.05 1/4d - £1.01.00d - 0.02.06d (all pounds shillings and pence)
Current weight 77.4 kg
